(4x-1)(2x+3)=18x-4
Aplicamos propiedad distributiva:
(4x)(2x)+ (4x)(3) + (-1)(2x) + (-1)(3) = 18x-4
8x² + 12x - 2x -3 = 18x-4
8x²+10x-3=18x-4
8x²+10x-18x -3+4=0
8x²-8x+1=0
Aplicamos formula resolvente o tambien llamado formula general:
-(-8) +/- √[(-8)²-4(8)(1)]
x= --------------------------------
2(8)
8+/-√[64-32]
x=----------------------
16
8+/-√32
x=----------------------
16
8+/- 4√2
x=---------------------- ........
16
2 +/- √2
x=--------------
4
Entonces:
2 + √2 2-√2
x1= -------------- y : x2= --------------
4 4
Conjunto Solucion: { (2+√2)/4 ; (2-√2)/4}
