OJO: ( Derivada de un conciente)
[tex]d ( \frac{u}{v} ) = \frac{ u'.v - u.v'}{v^2} [/tex]
[tex] \frac{dx^n}{dx} = n.x^{n-1}[/tex]
[tex] \frac{d c}{dx} = 0 , donde: c \ \ es \ una \ constante[/tex]
Por lo tanto:
[tex] \frac{d( \frac{2x-3}{3x+1} )}{dx} = \frac{(2x-3)' (3x+1) - (2x-3)(3x+1)'}{(3x+1)^2} [/tex]
[tex] \frac{d( \frac{2x-3}{3x+1} )}{dx} = \frac{(2 )(3x+1) - (2x-3)(3)}{(3x+1)^2} [/tex]
[tex] \frac{d( \frac{2x-3}{3x+1} )}{dx} = \frac{6x + 2 - 6x + 9}{(3x+1)^2} [/tex]
[tex] \frac{d( \frac{2x-3}{3x+1} )}{dx} = \frac{11}{(3x+1)^2} [/tex]
Eso es todo ;)
